Time Limit: 9000/3000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 7497Accepted Submission(s): 3865
当N = 0,输入结束。
1 #include<stdio.h> 2 #include<string.h> 3 #include<stdlib.h> 4 #define maxn 100000 5 int aa[maxn+5]; 6 intnn; 7 int lowbit(intx) 8 { 9 return x&(-x); 10 } 11 void ope(int x,intval) 12 { 13 while(x<=nn) 14 { 15 aa[x]+=val; 16 x+=lowbit(x); 17 } 18 } 19 int sum(intx) 20 { 21 int ans=0; 22 while(x>0) 23 { 24 ans+=aa[x]; 25 x-=lowbit(x); 26 } 27 returnans; 28 } 29 intmain() 30 { 31 inti,a,b; 32 while(scanf("%d",&nn),nn) 33 { 34 memset(aa,0,sizeof(aa)); 35 for(i=0;i<nn;i++) 36 { 37 scanf("%d%d",&a,&b); 38 ope(a,1); 39 ope(b+1,-1); 40 } 41 printf("%d",sum(1)); 42 for(i=2;i<=nn;i++) 43 printf("%d",sum(i)); 44 putchar(10); 45 } 46 return 0; 47 }