ReactNative踩坑日志——fetch如何向服务器传递参数

fetch(url?key1=val1&key2=val2&...).then((response) =>response.json())
            .then((json) =>{
                //处理返回值
            }).catch((error) =>{
             //异常处理
        })

fetch(url', {
  method: 'POST',
  headers: {
    'Accept': 'application/json',
    'Content-Type': 'application/json',
  },
  body: JSON.stringify({
    firstParam: 'yourValue',
    secondParam: 'secondValue',
  })
})

let formData = newFormData();  
formData.append("key",表单内容);  

fetch(url , {  
 method: 'POST',  
 headers: {},  
 body: formData,  
).then((response) =>{  
 if(response.ok) {  
     returnresponse.json();  
 }  
).then((json) =>{  
 alert(JSON.stringify(json));  
).catch((error) =>{  
 console.error(error);  
);