摘要：
选择。date_timeasdateTime，ifnull（b.order_num，'0.00'）asrderNum，ifnul（b.payment_amount，'0.00]）aspaymentAmountfrom（）aleftjoin（selectdate（create_date）asdate_time，order_num
select a.date_time as dateTime,ifnull(b.order_num,'0.00') as orderNum, ifnull(b.payment_amount,'0.00') as paymentAmount from ( <include refid="all_date"/> ) a
left join ( select date(create_date) as date_time, order_num, payment_amount from base_company_daily_data where company_id = #{companyId} ) b on a.date_time = b.date_time order by dateTime asc
某一天没有数据，结果中没有显示那天的数据，解决
<sql id="all_date"> SELECT date_sub(curdate(), interval 0 day) as date_time union all SELECT date_sub(curdate(), interval 1 day) as date_time union all SELECT date_sub(curdate(), interval 2 day) as date_time union all SELECT date_sub(curdate(), interval 3 day) as date_time union all SELECT date_sub(curdate(), interval 4 day) as date_time union all SELECT date_sub(curdate(), interval 5 day) as date_time union all SELECT date_sub(curdate(), interval 6 day) as date_time union all SELECT date_sub(curdate(), interval 7 day) as date_time union all SELECT date_sub(curdate(), interval 8 day) as date_time union all SELECT date_sub(curdate(), interval 9 day) as date_time union all SELECT date_sub(curdate(), interval 10 day) as date_time union all SELECT date_sub(curdate(), interval 11 day) as date_time </sql>
参考https://blog.csdn.net/ouyang111222/article/details/77638826