摘要：
可以通过Gson使用两种方法，将json字符串转换为对象，以下面该段报文做测试{"id":84041462,"lastName":"小华","age":32,"balance":666255.32,"hobbyDesc":{"subject":"数学","score":25,"sport_desc":"跑步有益健康"}}1.创建实体类，通过fromJson方法将json数据封装进对象中如上，将上面
可以通过Gson使用两种方法，将json字符串转换为对象，以下面该段报文做测试
{ "id": 84041462, "lastName": "小华", "age":32, "balance":666255.32, "hobbyDesc": { "subject": "数学", "score":25, "sport_desc":"跑步有益健康" } }
如上，将上面报文按层次解析并创建两个对象
importcom.google.gson.annotations.SerializedName; public classHobbyDesc { privateString subject; private intscore; @SerializedName("sport_desc") privateString sportDesc; //***
public classAccount { privateString id; privateString lastName; private intage; private doublebalance; privateHobbyDesc hobbyDesc;
//***
解析
String jsonStr = "{
" +
" "id": 84041462,
" +
" "lastName": "小华",
" +
" "age":32,
" +
" "balance":666255.32,
" +
" "hobbyDesc": {
" +
" "subject": "数学",
" +
" "score":25,
" +
" "sport_desc":"跑步有益健康"
" +
" }
" +
"
" +
"}";
Account account =newGson().fromJson(jsonStr,Account.class);
同时也可以看到，对象中定义为字符串类型的字段也可以接受json串的数值类型，没有转换问题。
2. 解析为jsonObject对象直接使用Gson API解析
String jsonStr = "{
" +
" "id": 84041462,
" +
" "lastName": "小华",
" +
" "age":32,
" +
" "balance":666255.32,
" +
" "hobbyDesc": {
" +
" "subject": "数学",
" +
" "score":25,
" +
" "sport_desc":"跑步有益健康"
" +
" }
" +
"
" +
"}";
JsonObject jsonObject = (JsonObject) newJsonParser().parse(jsonStr);
System.out.println("id <getAsInt> = "+jsonObject.get("id").getAsInt());//id <getAsInt> = 84041462
System.out.println("id <getAsString> = "+jsonObject.get("id").getAsString());//id <getAsString> = 84041462
System.out.println("position = "+ jsonObject.get("hobbyDesc").getAsJsonObject().get("sport_desc").getAsString());//position = 跑步有益健康参照jsonObject结构，可以了解Gson这种封装对象的方式，如果仅仅是取某值的话，可以采用这种方式，可以节约大量时间
